THE PRACTICE TEST
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5 grams of solute dissolved in 100 mL of solution w/v stands for weight/volume. It is used for solid solutes dissolved in liquid solvents.- Weight refers to the weight of the solute and is measured in grams.
- Volume refers to the final volume of the solution and is measured in mL.
5 grams of solute dissolved in 100 mL of solvent 5 mL of solute dissolved in 100 mL of solution 5 mL of solute dissolved in 100 mL of solvent
0.002 mol/dm³ 2 mol/dm³ First, we need to convert cm³ to dm³. Since one dm³ is a thousand times larger than one cm³, we need to divide the number of cm³ by 1,000:250/1,000 = 0.25 dm³ Now we can work out the concentration. The concentration formula is:concentration = amount of solute/volume Inserting the values into the formula gives:concentration = 0.5/0.25 = 2 mol/dm³ 12.5 mol/dm³ 125 mol/dm³
0.065 g/dm³ 18.25 g/dm³ To convert moles to grams:moles × molar mass = grams This formula can also be used to convert mol/dm³ to g/dm³:mol/dm³ × molar mass = g/dm³ Inserting the values from the question into this formula gives us:0.5 mol/dm³ × 36.5 = 18.25 g/dm³ 36.55 g/dm³ 73 g/dm³
0.5 dm³ 0.75 dm³ 1 dm³ 2 dm³ The concentration formula is:concentration = amount/volume We can rearrange this formula to:volume = amount/concentration Inserting the values into the formula gives us:volume = 1/0.5 = 2 dm³
MgO To find the empirical formula, start by converting the masses of each element into moles.moles of magnesium = mass/atomic mass Since there are 0.2 moles of magnesium and oxygen, the ratio of magnesium to oxygen in magnesium oxide is 1:1. Based on this 1:1 ratio, the empirical formula for magnesium oxide is MgO.moles of magnesium = 4.8 g/24moles of magnesium = 0.2 moles of oxygen = mass/atomic massmoles of oxygen = 3.2 g/16moles of oxygen = 0.2MgO₂ MgO₃ Mg₃O
1 ppm The formula for calculating parts per million (ppm) is:ppm = (mass of solute/mass of solution) × 1,000,000 Inserting the values into the formula:ppm = (0.001 g/1,000 g) × 1,000,000 ppm = 0.000001 × 1,000,000ppm = 1 ppm10 ppm 100 ppm 1,000 ppm
0.05 mol 0.8 mol The concentration formula is:concentration = amount of solute/volume of solution The question asks us to find the amount of solute. Therefore, we need to rearrange the formula to solve for the amount of solute:solute amount = concentration × volume Inserting the values into the rearranged formula:solute amount = concentration × volume solute amount = 0.2 mol/dm³ × 4 dm³solute amount = 0.8 mol3.8 mol 4.2 mol
58 mL 101 mL 391 mL A solute-to-solvent dilution ratio of 7:10 means the solution contains 7 parts solute and 10 parts solvent, making 17 parts in total. In other words, 7/17ths of the solution is solute. To find the volume of solute in a solution, multiply the volume of the final solution by the fraction of the solution that is solute:950 mL × 7/17 = 391 mL of solute 559 mL
To help identify the sample if the container is misplaced To prevent air from entering the container To show whether the container has been tampered with Custody seals provide proof if a container has been opened or tampered with. They are commonly used in forensic testing to protect the integrity of the sample.To show who currently has custody of the container
Only the courier Only the laboratory technician The courier and the laboratory technician Every time a chain of custody sample changes hands, the person giving it and the person receiving it must sign and date the chain-of-custody form.The laboratory manager and the laboratory technician
Corrosive Class 8 hazardous materials are corrosives. They destroy living tissue and corrode metals. They include acids and bases that can cause chemical burns on contact.Explosive Poisonous Radioactive
Explosive Class 1 hazardous materials are explosives.Infectious Poisonous Radioactive
Chemicals and noise OSHA action levels are for hazardous chemicals and occupational noise. An action level is a level of exposure that requires employers to take action. Examples of chemicals with OSHA action levels include formaldehyde, lead, and respirable crystalline silica.Ergonomic hazards Psychosocial hazards Slips, trips, and falls
−5°C 2°C 6°C Samples for any kind of organic test must be kept below 6°C.10°C
Bloodborne pathogens Dangerous chemicals OSHA’s Hazard Communication Standard requires employers to inform workers about the hazards of dangerous chemicals used in the workplace.General safety hazards Miscommunication
1 2 4 8 Most OSHA PELs are 8-hour time-weighted averages.
19.5% According to OSHA, the minimum safe oxygen level in a confined space is 19.5%. If the oxygen level is below this, you'll need to wear respiratory protection.20.1% 20.4% 20.9%
85 dB 90 dB 95 dB 100 dB
Aerated grit chamber Air lift Clarifier Hydrocyclone Hydrocyclones are typically used to separate grit from organics in grit slurries and to remove grit from primary sludge. These devices spin the grit out of the slurry using centrifugal force.
0.5 The formula for the F/M ratio is:F/M ratio = BOD per day in lbs/MLVSS in lbs Inserting the values into the formula:F/M ratio = 75,000 lb/150,000 lb F/M ratio = 0.51 1.5 2
Temperature Total toxic organics Turbidity pH
Methylene blue Anionic surfactants in a water sample can be detected with a methylene blue active substances (MBAS) assay. This is a colorimetric analysis test method that uses methylene blue.Nile red Oil red Thymolphthalein
At room temperature In a freezer In a refrigerator Samples can degrade quickly. If you cannot start a BOD₅ test within two hours of collecting the sample, you should chill the sample (at a temperature of 1–4°C).In a vacuum flask
0.1 hours 10 hours The formula for hydraulic retention time is:hydraulic retention time = volume/flow rate Inserting the values into the formula:hydraulic retention time = 100/10 hydraulic retention time = 10 hours100 hours 1,000 hours
Has a restricted entry and exit, contains serious safety hazards, and is large enough to work in Has a restricted entry and exit, contains serious safety hazards, and is too small to work in Has a restricted entry and exit, is not meant for continuous occupancy, and is large enough to work in Has a restricted entry and exit, is not meant for continuous occupancy, and is too small to work in
Anaerobic conditions in the aeration basin Dark sudsy foam with a septic or sour odor is a sign of anaerobic conditions in the aeration basin. Check DO levels in the basin and increase aeration/mixing. Reduce organic loading if possible.Filamentous organisms are present The RAS flow is too low The aeration basin has excessive solids due to insufficient wasting
Primary The objective of primary treatment is to remove settleable solids by sedimentation and to remove materials that will float (scum) by skimming.Secondary Tertiary Quarternary
CFS CFS stands for cubic feet per second and is a typical unit used to measure flow. Other units used to measure flow are GPM (gallons per minute) and MGD (million gallons per day)MPH liters mg/L
nitrate and ammonia nitrate and nitrite organic nitrogen and ammonia organic nitrogen and nitrite
20 CFR Part 136 20 CFR Part 1910.1450 40 CFR Part 403 40 CFR Part 503
banners billboards chairs flagmen
mEq OH− mEq/kg mg/L CaCO₃ In the US, water alkalinity is usually reported as mg/L CaCO₃ since most alkalinity is derived from the weathering of carbonate minerals. Alkalinity can also be reported in milliequivalents per liter (mEq/L).mol NaOH
0.1 mL, 0.3 mL, 0.6 mL 100 mL, 300 mL, 600 mL 200 mL, 600 mL, 1,200 mL Step 1) Add up the discharge rates100 + 300 + 600 = 1,000 gpd Step 2) Calculate the fraction for each connection- 100/1000 = 0.1
- 300/1000 = 0.3
- 600/1000 = 0.6
- 0.1 x 2,000 mL = 200 mL
- 0.3 x 2,000 mL = 600 mL
- 0.6 x 2,000 mL = 1,200 mL
500 mL, 750 mL, 750 mL
Carbohydrates Fats Fats are classified as slowly biodegradable substances. Among the options, fats take the longest to biodegrade in wastewater. For this reason, the removal of fats often requires specific processes in wastewater treatment to enhance their breakdown.Glucose Proteins
To accelerate sedimentation To destroy microorganisms Chlorine is the most common type of drinking water disinfection. It kills bacteria, viruses, and other microorganisms in drinking water that would otherwise cause disease and illness.To enhance water taste and odor To reduce water hardness
1.7 acres 2.3 acres First, calculate the area of the pond in square feet. The formula to calculate area is:area = length × width Inserting the values into the formula:area = 500 × 200 To convert square feet to acres, divide the number of square feet by 43,560:area = 100,000 square feet100,000/43,560 = 2.2957 acres Rounded to one decimal place, the pond's surface area is approximately 2.3 acres.3.8 acres 4.5 acres
distance energy pressure PSI stands for "pounds per square inch" and is a unit of pressure.time
Milligallons per day Milligrams per day Million gallons per day MGD is a measurement of water flow and means million gallons per day.Thousand gallons per day
vacuum channel verified capacity vinyl chloride vitrified clay Vitrified clay pipe (VCP) is pipe made from a blend of clay and shale that has been subjected to high temperature to achieve vitrification, which results in a hard, inert ceramic.
30 minutes 8 hours 28 hours 7 days
composite discrete sequential time-proportional
Nitrate has three hydrogen atoms while nitrite has two Nitrate has three oxygen atoms while nitrite has two Nitrate is NO₃ (one nitrogen atom and three oxygen atoms) while nitrite is NO₂ (one nitrogen atom and two oxygen atoms).Nitrate has two hydrogen atoms while nitrite has three Nitrate has two oxygen atoms while nitrite has three
Filtrate Sewage Slush Supernatant The supernatant is the relatively clear water layer between the sludge on the bottom and the scum on the surface of an anaerobic digester.
4.5 4.6 4.7 4.8 Step 1) Sum the results 4.7 + 5.1 + 5.4 + 6.2 + 6.1 + 5.9 + 4.2 + 3.5 + 3.5 + 3.4 = 48 Step 2) Divide the sum by the number of results48/10 = 4.8
Water from sinks, showers, bathtubs, and washing machines Water that contains soil Water that has been cleaned at a water treatment plant Water that has come into contact with feces
guidelines establishing test procedures for the analysis of pollutants hazardous waste injection restrictions state UIC program requirements toxic pollutant effluent standards
oxidation of ammonia oxidation of nitrate reduction of ammonia reduction of nitrate Denitrification is the reduction (removal of oxygen) of nitrate to form nitrogen gas.
Dechlorination Dechlorination is the process of removing residual chlorine from disinfected wastewater. Sulfur dioxide is the most common method of dechlorination.Digestion Disinfection Thickening
Employer workplace rights The storage of dangerous chemicals The thickness of pipes Wastewater legislation
BOD Cyanide Nitrates Polychlorinated biphenyl
Grit removal Grit removal – the process of settling out heavy particles like sand and gravel – is the step after screening.Screening Screening is the first stage of wastewater treatment. The aim of screening is to remove objects such as rags, paper, and plastics to prevent clogging of equipment further downstream.Sedimentation Trickling filters
2.9 PSI 14.0 PSI 28.2 PSI 43.3 PSI Pressure is measured in either PSI (pounds per square inch) or feet of head. To convert from feet of head to PSI, multiply by 0.433:100 feet of head × 0.433 = 43.3 PSI
Contact details of the maintenance contractor HHE-200 septic permit number Name of the inspector Signature of the plant manager
2 hours Step 1. Convert the flow rate to gallons per hour MGD means million gallons per day. A day has 24 hours, so to convert MGD into hours, divide by 24:2,400,000/24 = 100,000 gallons per hour Step 2. Calculate the detention time The formula for detention time is:detention time = volume/flow rate Inserting the values into the formula:detention time = 200,000/100,000 detention time = 2 hours2.5 hours 3.5 hours 3 hours
caustic soda Lye and caustic sodium are terms for sodium hydroxide.lye quick lime Quick lime, also called caustic lime, is another term for calcium oxide.slaked lime Slaked lime is the common name for calcium hydroxide.
Department of Energy (DOE) Environmental Protection Agency (EPA) Food and Drug Administration (FDA) Occupational Safety and Health Administration (OSHA)
120 mg/L Step 1) Calculate the dilution factor The formula for dilution factor is:dilution factor = total volume/sample volume Inserting the values into the formula:dilution factor = 300/100 = 3 Step 2) Calculate the BOD₅ The formula for BOD₅ is:(initial DO − final DO) × dilution factor Inserting the values into the formula:BOD₅ = (50 − 10) × 3 BOD₅ = 40 × 3BOD₅ = 120 mg/L245 mg/L 500 mg/L 600 mg/L
Ammonia Chromium Cyanide Oil Conventional pollutants are any water pollutants that can be treated by a municipal sewage treatment plant. Examples of conventional pollutants are oil, grease, biochemical oxygen demand, total suspended solids, fecal coliform, and pH.
Bottles of clean water Field blanks are simply samples of clean water. They are carried with the field samples. They can tell you if contamination was accidentally introduced during sample collection.Collection systems of unknown water quality Disposable, single-use sampling devices Water samples taken upstream from incoming pollutants
$10,835 $15,615 $31.23 × 500 = $15,615$20,935 $25,815
area depth pressure differential voltage
gas detector pH meter power grinder sampling pump
Ammonia Nitrate Nitrate is the most oxidized form of nitrogen found in wastewater. The molecule has three oxygen atoms. Nitrate only has two oxygen atoms and ammonia has none.Nitrite Organic nitrogen Organic nitrogen is the nitrogen atoms that occur in organic compounds.
2 6 10 Step 1: Calculate the total daily wastewater The question asks how long the system needs to process a day's wastewater. 0.12 MGD means "0.12 million gallons per day" which means the factory produces 120,000 gallons of wastewater in one day. Therefore a day's wastewater is 120,000 gallons. Step 2: Understand the treatment system capacity GPM means "gallons per minute". 200 GPM means the treatment system can process 200 gallons every minute. Step 3: Calculate the time required in minutes If the system can process 200 gallons a minute, we can work out how many minutes it would take to process 120,000 gallons:120,000 gallons/200 GPM = 600 minutes Convert minutes to hours To convert from minutes to hours, divide by 60:600/60 = 10 hours 14
Fire extinguisher First aid kit Spill control pillows Stop signs A fire extinguisher, first aid kit, and spill control pillows must be in each inspector's vehicle.
EPA The EPA (Environmental Protection Agency) enforces the Clean Water Act and ensures that pretreatment facilities comply with it.NOAA The Department of Energy The Department of Health and Human Services
The density of the sludge handled Solids in primary clarifiers are typically inorganic and less dense. In contrast, solids in secondary clarifiers are nearly 100% organic and compact readily, making the sludge far denser.The flow rate through the clarifiers The number of clarifiers required The sludge removal systems
12.5 g/day 225 g/day The formula for mass emission rate is:concentration × flow rate The question tells us:- concentration = 4.5 mg/L
- flow rate = 50,000 L per day
mass emission rate = 50,000 × 4.5 Finally, to convert from milligrams to grams, divide by 1,000:mass emission rate = 225,000 mg per day225,000 mg/1,000 = 225 g 5 g/day 90 g/day
Carbon monoxide Hydrogen cyanide Hydrogen sulfide Methane
50 The range is the difference between the highest result and the lowest result. In this case, the range is 242 − 192 = 50.100 150 200
Rainwater The cleaner the water, the lower the BOD. Untreated municipal water has the highest BOD while rainwater, being the cleanest, has the lowest BOD.Treated municipal water Unpolluted river water Untreated municipal water
2,100 3,800 4,700 Step 1) Calculate the volume of the spill The spill can be imagined as a cylinder. The formula for calculating the volume of a cylinder is:volume = π × radius² × height Inserting the values into the formula:volume = π × 10² × 2 Step 2) Convert the volume to gallons To convert from cubic feet to gallons, multiply by 7.48:volume = π × 100 × 2volume = π × 200volume = 628.4 ft³628.4 cubic feet × 7.48 = 4,700 gallons Therefore, the estimated volume of the spill is approximately 4,700 gallons.5,300
time-proportional discrete A composite sample is collected by combining discrete (a.k.a. grab) samples.aggregate flow-proportional
V = (1.49/A) × n²ᐟ³ × S × √R V = (1.49/n) × A × R²ᐟ³ × √S Manning's formula describes the relationship between the flow velocity, cross-sectional area, hydraulic radius, and slope in open channel flows. Manning's formula states that the flow velocity (V) is equal to a constant (1.49) divided by the roughness coefficient (n), multiplied by the cross-sectional area of flow (A), multiplied by the hydraulic radius (R) raised to the power of 2/3, and multiplied by the square root of the slope of the channel (S).V = (A/1.49) × n × R²ᐟ³ × √S V = (n/1.49) × A²ᐟ³ × S × √R
Liquefactant Liquescent Surfactant Surfactants are molecules that lower the surface tension of liquids. Surfactants commonly have one end that is hydrophilic and the other that is hydrophobic.Tensile
Calcium and magnesium Water hardness measures the amount of calcium and magnesium present in water.Iron and phosphorous Nitrogen and oxygen Sodium and fluoride
Ensure safe drinking water Prevent damage to POTWs The primary purpose of the General Pretreatment Regulations is to prevent the discharge of pollutants that could damage POTWs (publicly owned treatment works). This includes pollutants that are a fire or explosion hazard, pollutants that can corrode infrastructure, and pollutants that could obstruct the flow in the POTW.Promote wildlife conservation Regulate air quality
Composite Flow-proportional Grab Grab samples are one-off samples. They are the most common type of sample.Time-proportional
Fluid pressure reduces when the fluid flows through a constricted section of a pipe The Venturi effect describes how the velocity of a fluid increases and the pressure decreases as the pipe becomes more constricted.Fluids have constant densities, regardless of pressure variations in the flow Fluids passing from higher to lower elevations maintain a steady velocity In a steady flow, the sum of all forms of energy in a fluid along a streamline is the same at all points on that streamline
Breweries Wastewater from breweries is high in sugar and alcohol, causing very high levels of total suspended solids.Laundries Oil fields Textile dyehouses
By calling the police and fire departments By contacting local TV and radio stations By making one call to a person in the home office By phoning the collection system and treatment plant superintendents
Chemical ordering plan Future expansion plan Spare parts inventory plan Spill prevention plan
Direct and indirect Municipal and industrial Raw and treated Sanitary and storm
0.5 grams 2 grams 500 grams Step 1) Convert g/mL to g/L The question gives the density in g/mL but asks you for the number of grams in one liter (g/L). Therefore the first step is to convert from g/mL to g/L. To convert g/mL to g/L, multiply by 1,000:2 g/mL × 1,000 = 2,000 g/L Step 2) Calculate 25% of the total Multiply by 0.25 to find the amount of sodium chloride:2,000 g/L × 0.25 = 500 g/L Therefore, one liter of the solution has 500 grams of sodium chloride.2,000 grams
Acetic acid Carbon tetrachloride Gasoline Hexavalent chromium
26,928 Step 1) Convert ft³ to gallons First, convert the flow rate from cubic feet to gallons. To do this, multiply by 7.48:1 cubic foot × 7.48 = 7.48 gallons Step 2) Convert seconds to hours The flow rate is 7.48 gallons per second. To convert this to hours, multiply by 3,600 (the number of seconds in an hour):7.48 × 3,600 = 26,928 gallons per hour Therefore, a flow rate of one cubic foot per second is equal to 26,928 gallons per hour.37,818 42,470 58,915
2 3 5 10
12 minutes 28 minutes 37 minutes 43 minutes Step 1: Calculate the detention time in days The formula for detention time is:detention time = volume/flow rate Inserting the values into the formula:detention time = 3,000/100,000 Step 2: Convert from days to minutes Convert from days to minutes by multiplying by 1,440 (the number of minutes in a day):detention time = 0.03 days0.03 × 1,440 = 43.2 minutes Therefore, the average detention time is approximately 43 minutes.
a briefing for public officials a case for court if enforcement action is initiated a meeting for reporters an informational pamphlet for the public
Field test kits Field test kits are not as accurate or detailed as laboratory tests.Laboratory chemical tests The best method to determine the pollutants that industrial dischargers are placing in collection systems is laboratory chemical tests. Laboratory chemical tests provide a more comprehensive and accurate analysis of pollutants than the other options.Results of industrial self-monitoring Visual observations
2.8 hours Step 1) Calculate the volume of the tank A batch tank is a cylinder. The formula for calculating the volume of a cylinder is:volume = π × radius² × height Inserting the values into the formula:volume = π × 3² × 8 Step 2) Convert the volume to gallons To convert from cubic feet to gallons, multiply by 7.48:volume = π × 9 × 8volume = π × 72volume = 226.2 ft³226.2 cubic feet × 7.48 = 1691 gallons Therefore, the estimated volume of the batch tank is approximately 1691 gallons. Step 3) Calculate the number of minutes The question says the tank has a discharge rate of 10 GPM (gallons per minute). The formula for discharge rate is:discharge rate = volume/time We can rearrange this formula:time = volume/discharge rate Inserting the values into the formula:time = 1691/10 = 169.1 minutes Step 4) Convert minutes to hours To convert from minutes to hours, divide by 60:169.1 minutes/60 = 2.8 hours Therefore, the batch tank will take approximately 2.8 hours to empty.4.2 hours 7.4 hours 9.6 hours
collected during minimum flows obtained when industrial representatives are present similar to the larger body of the waste stream being sampled transported to a laboratory for analysis
A record of criminal action against an industrial discharger A record of each agency action leading to a notice of violation A record of every person who has access to a sample A record of every sample submitted to the laboratory
biological organisms bound oxygen dissolved oxygen organic material Biochemical oxygen demand (BOD) indicates the amount of organic material in water. Specifically, BOD is the amount of dissolved oxygen needed by aerobic organisms to break down all the organic material in the water.
Facultative Facultative ponds have an aerobic zone at the top and an anaerobic zone at the bottom. The aerobic conditions at the top are created by algae. The anaerobic conditions at the bottom are created by the high demand for oxygen in the settled solids.Aerobic Anaerobic Maturation
Fats, oils, and grease Filamentous organisms Free oxygen grade Fully organic grade
dispose of minimize Pollution prevention means eliminating or reducing the amount and toxicity of potentially harmful substances at their sources, before generation, treatment, recycling or disposal.recycle treat
Comprehensive Environmental Response, Compensation and Liability Act Resource Conservation and Recovery Act Superfund Amendments and Reauthorization Act Toxic Substances Control Act
a pretreatment facility the centralized waste treatment facility the environment the wastewater collection system
Pipe corrosion Pathogen growth Carcinogenicity Toxic gas
Continuous Discrete Flow-proportional Flow-proportional samples are taken every x number of gallons discharged.Time-proportional
110,547 gallons Step 1) Calculate the area of the rectangle The formula to calculate the area of a rectangle is:area = length × width Inserting the values into the formula:10 m × 5 m = 50 m² Step 2) Calculate the area of the semi-circle The formula to calculate the area of a circle is:area = π × radius² The diameter is 5 meters, so the radius is 2.5 meters. Inserting the values into the formula:area = π × 2.5² Since we are dealing with a semi-circle, we divide by 2:area = π × 6.25area = 19.6 m²19.6/2 = 9.8 m² Step 3) Calculate the total area50 m² + 9.82 m² = 59.82 m² Step 4) Calculate the volume of water in m³ Multiply the water area by the water depth to find the water volume:59.82 m² × 7 m = 418.74 m³ Step 5) Convert m³ to liters To convert m³ to liters, multiply by 1,000:418.74 m³ × 1,000 = 418,740 liters Step 6) Convert the liters to gallons To convert liters to gallons, multiply by 0.264:418,740 × 0.264 = 110,547 gallons 222,938 gallons 319,937 gallons 483,885 gallons
Carbon monoxide Hydrogen sulfide Hydrogen sulfide turns lead acetate paper brown or black.Methane Nitrogen dioxide
copper mercury silicon steel
5 minutes 5 hours 5 days The BOD₅ test measures the biological oxygen demand of a water sample over five days.5 weeks
10 hours The formula for flow rate is:flow rate = volume/time We can rearrange this formula to solve for time:time = volume/flow rate Inserting the values into the formula:time = 60,000/100 = 600 minutes To convert from minutes to hours, divide by 60:600/60 = 10 hours Therefore, the facility can process 60,000 gallons in 10 hours.12 hours 14 hours 16 hours
aerobic on the top and anaerobic on the bottom anaerobic on the top and aerobic on the bottom wholly aerobic Maturation ponds have aerobic conditions throughout, from the surface to the bottom.wholly anaerobic
amount of solids removed from an activated sludge reactor concentration of suspended solids in mixed liquor of an aeration tank MLSS stands for Mixed Liquor Suspended Solids and is the concentration of suspended solids in mixed liquor of an aeration tank.mixture of wastewater and microorganisms returned to the head of an aeration tank underflow from a secondary sedimentation tank
Sanitary sewer overflow SSO stands for sanitary sewer overflow. SSO occurs when a sanitary sewer overflows and discharges untreated sewage into the environment.Single source outlet Surface-to-surface outfall Suspended solids and organics
Fat-to-mineral ratio Flotsam-to-mixture ratio Flow-to-mass ratio Food-to-microorganism ratio The F/M ratio is the ratio of food (measured as BOD, COD, or TOC) to microorganisms.
The Environmental Protection Agency The facility's safety officer The local government The owner or operator of the facility For facilities where an SPCC is necessary, it is the responsibility of the owner or operator of the facility to prepare and implement an SPCC Plan.
21,308 gallons 22,839 gallons 24,810 gallons 26,703 gallons Step 1) Find the volume of tank 1 The first tank is a cuboid, so we use the formula:volume = length × width × height Step 2) Find the volume of tank 2 The second tank is rectangular, so we use the same formula:volume = 5 ft × 5 ft × 5 ftvolume = 125 ft³volume = length × width × height Step 3) Find the volume of tank 3 The third tank is a cylinder, so we use the formula:volume = 30 ft × 10 ft × 3 ftvolume = 900 ft³volume = π × radius² × height The diameter is 18 feet so the radius is:radius = 18/2 = 9 feet Inserting the values into the formula:volume = π × 9² × 10 Step 4) Sum the volumes of the tanks Sum the volumes of the three tanks.volume = π × 81 × 10volume = π × 810volume = 2,545 ft³125 ft³ + 900 ft³ + 2,545 ft³ = 3,570 ft³ Step 5) Convert to gallons Convert ft³ to gallons by multiplying by 7.48:3,570 ft³ × 7.48 = 26,703 gallons
Ask a supervisor Ask an employee who works there Check the PPE policy Check the SDS Consulting the safety data sheet is the best place to begin when deciding on what type of protective gear to use.
9.4 The formula for calculating the average is:average = sum/count First, sum up the results:9.1 + 9.5 + 8.9 + 9.5 + 10.0 = 47 Then, divide the sum by the number of results:47/5 = 9.4 9.5 9.6 9.7
Carcinogenicity Polychlorinated biphenyls are highly carcinogenic. For this reason, their production has been banned in the United States.Combustibility Flammability Toxicity
1 2 3 4 To convert inches of water column to psi, divide by 27.7:110.8/27.7 = 4 psi
To check the effluent quality To meet with a POTW's normal contact person To review paperwork To test the response of the industry
CH₃COOH Ca(OH)₂ Ca(OH)₂ (calcium hydroxide, also known as lime) is a strong alkaline and can be used to neutralize acidic wastewater. CH₃COOH (acetic acid), HCl (hydrochloric acid), and HNO₃ (nitric acid) are all acids and would not neutralize acidic wastewater.HCl HNO₃
2 4 6 12 The effluent from Significant Industrial Users should be sampled at least once a year.
10,001 28,376 48,103 66,138 Step 1) Convert from kg to lb To convert from kilograms to pounds, multiply the kilograms by 2.2:10,000 × 2.2 = 22,046 pounds Step 2) Calculate the pounds of sodium bisulfite needed The question says 3 pounds of sodium bisulfite are needed for every 1 pound of hexavalent chromium. So to find the number of pounds of sodium bisulfite needed, we multiply the number of pounds of hexavalent chromium by 3.22,046 × 3 = 66,138 pounds
HCl to pH < 9 HNO₃ to pH > 9 H₂SO₄ to pH < 2 H₂SO₄ (sulfuric acid) is the correct preservative for TKN samples.Zinc acetate + NaOH to pH < 2
HCl While HCl (hydrochloric acid) is a strong acid, it is not used to preserve samples for total phosphorus tests. Instead, HCl is used as a preservative for the analysis of total organic carbon, total dissolved carbon, iron, methane, oil and grease, and volatile organic compounds.H₂SO₄ Samples for total phosphorus analysis must be kept at a pH below 2. Strong acids such as H₂SO₄ (sulfuric acid) and HNO₃ (nitric acid) are appropriate preservatives.KOH KOH (potassium hydroxide) is alkaline and therefore unsuitable.NaOH NaOH (sodium hydroxide) is alkaline and therefore unsuitable.
Carbon Hydrogen pH is the measurement of the hydrogen ion concentration in a liquid.Nitrogen Oxygen
very acidic slightly acidic neutral slightly alkaline
0 1 3 7 The pH scale ranges from 0 to 14, where 0 is extremely acidic, 14 is extremely basic (or alkaline), and 7 is neutral (meaning neither acidic nor basic).
cm³ dm³ mL/billion mg/L ppm stands for parts per million, which is a way of expressing very dilute concentrations of substances. 1 ppm means 1 part of a substance in 1,000,000 parts of the solution. In water solutions, 1 ppm is equivalent to 1 milligram of solute per liter of solution (mg/L), because 1 L of water ≈ 1 kg of water.
3 6 256 1,000 For each one-digit decrease in pH, the acidity increases by 10 times. This means:- A pH of 2 is 10 times more acidic than a pH of 3
- A pH of 2 is 100 times more acidic than a pH of 4
- A pH of 2 is 1,000 times more acidic than a pH of 5
0.2 mL To convert from microliters to milliliters, divide the value by 1,000:200 µL/1,000 = 0.2 mL 2 mL 20 mL 2,000 mL
0.0001 mcg 0.001 mcg 10,000 mcg To convert from milligrams to micrograms, multiply by 1,000:10 mg × 1,000 = 10,000 mcg 100 mcg
KOH KOH needs a coefficient of 2 for the equation to be balanced:2KOH + CO₂ → K₂CO₃ + H₂O This balances the number of atoms for each element on both sides of the equation. Now each side has 2 potassium (K) atoms, 4 oxygen (O) atoms, 2 hydrogen (H) atoms, and 1 carbon (C) atom.CO₂ K₂CO₃ H₂O
2Ag + H₂S → Ag₂S + H₂ In the unbalanced equation, the left-hand side has one Ag atom, but the right-hand side has two Ag atoms. Therefore, the left-hand side needs one more Ag atom to balance the equation.4Ag + 2H₂S → 2Ag₂S + H₂ 2Ag + 2H₂S → Ag₂S + 4H₂ 4Ag + H₂S → 2Ag₂S + H₂
15,000 75,000 150,000 The titration formula isM₁ × V₁ = M₂ × V₂ where:- M₁ is the molarity of solution 1
- V₁ is the volume of solution 1
- M₂ is the molarity of solution 2
- V₂ is the volume of solution 2
HCl + KOH = KCl + H₂O This equation shows that HCl and KOH react in a 1:1 molar ratio. Therefore, we do not need to adjust the stoichiometry in the calculation. Using the titration formula:M₁ × V₁ = M₂ × V₂ 0.5 × 30,000 gallons = 0.1 × V₂ 15,000 = 0.1 × V₂ 15,000/0.1 = V₂ 150,000 gallons = V₂ 450,000
0.4 M First, write the balanced chemical equation for the reaction:HBr + LiOH = LiBr + H₂O The equation shows that 1 mole of HBr reacts with 1 mole of LiOH. Therefore, we do not need to adjust the stoichiometry in the calculation. Using the titration formula:M₁ × V₁ = M₂ × V₂ 0.5 × 20 = M₂ × 25 10 = M₂ × 25 10/25 = M₂ 0.4 = M₂ 0.5 M 0.6 M 0.75 M
0.005 M 0.045 M 0.5 M 1 M Step 1) Write the balanced equation.H₂SO₄ + 2KOH = K₂SO₄ + 2H₂O This equation shows that H₂SO₄ (sulfuric acid) and KOH (potassium hydroxide) react in a 1:2 molar ratio. Step 2) Calculate the moles of KOH used in the titration:moles = molarity × volume Step 3) Calculate the moles of H₂SO₄. Since 1 mole of H₂SO₄ reacts with 2 moles of KOH, we need to divide the number of moles of KOH by 2 to find the number of moles of H₂SO₄:moles = 0.1 M × 1 Lmoles = 0.1 moles0.1 moles/2 = 0.05 moles Step 4) Calculate the molarity of the H₂SO₄ solution:molarity = moles/volume Therefore, the molarity of the H₂SO₄ solution is 1 M.molarity = 0.05/0.05molarity = 1 M
2% 4% 7% 12% Carbon monoxide has a lower flammability limit of 12%. This means concentrations of carbon monoxide below 12% cannot catch fire.
1% 5% Methane has a lower flammability level of around 5%. If the atmosphere has less than 5% methane, an explosion cannot occur even if a source of ignition is present.10% 17%
Category 1 Category 2 Category 3 Category 1 and 2 liquids have flashpoints below 23 °C. Category 3 liquids have flashpoints of 23–60 °C. Category 4 liquids have flashpoints of 60–93 °C.Category 4
The amount of fuel that will burn before the fuel burns itself out The highest concentration of a vapor that can catch fire The upper flammability limit is the highest concentration of a vapor in air that can burn. Above this limit, there is not enough oxygen for the vapor to burn.The highest temperature at which a liquid can be stored safely The highest temperature that a chemical can reach when ignited
37.8°C 67.3°C 93°C The Occupational Safety and Health Administration (OSHA) defines a flammable liquid as any liquid with a flash point at or below 93°C.100°C
Short-term exposure limit The short-term exposure limit (STEL) is the amount of a substance that people can be exposed to over 15 minutes without harmful health effects.Standard task exposure limit Standard task equipment list Short-term emergency lighting
Level A Level B Level C Level D Safety goggles are level D PPE, the lowest level of personal protection equipment. Higher levels of PPE (A, B, and C) require the user to wear face masks or totally encapsulating suits instead.
Carcinogen A carcinogen is any substance that can cause cancer in humans or animals. The word comes from carcino meaning "cancer" and gen meaning "causing".Caustic substance Nosocomial substance Pathogenic substance
CH₄ C₂H₈ C₈H₂ C₈H₈
CO₂ H₂O This is a neutralization reaction between an acid (HCl) and a base (Mg(OH)₂). The products of neutralization reactions are always salt (MgCl₂ in this case) and water (H₂O).O₂ O₃
HS HS₂ H₂S H₂S₂
0.8 g/mL 0.9 g/mL 1.25 g/mL The formula for calculating density is:density = mass/volume Inserting the values into the formula:density = 50 g/40 mL density = 1.25 g/mL1.5 g/mL
The concentration a worker can be exposed to for one hour without adverse effect The concentration a worker can be exposed to over a working lifetime without adverse effects The concentration a worker can be exposed to up to 4 times per day The concentration that should never be exceeded TLV-C stands for Threshold Limit Value Ceiling. It is the exposure limit that should not be exceeded at any time.
81.25 ppm The formula for calculating the average is:average = sum/count In this case:- sum is the sum of the ppm for each hour
- count is the total number of hours (8)
2 hours × 150 ppm = 300 ppm-hours 2 hours × 75 ppm = 150 ppm-hours 4 hours × 50 ppm = 200 ppm-hours 300 + 150 + 200 = 650 ppm Then, divide the sum by the total number of hours:650 ppm-hours/8 hours = 81.25 ppm 88.515 ppm 91.75 ppm 95 ppm
5 minutes 15 minutes The STEL (short-term exposure limit) is the concentration of a substance a worker can be exposed to over a short period (usually 15 minutes) without injury.1 hour 8 hours
pH 1 pH 4 pH 7 When calibrating a pH meter, a neutral buffer of pH 7 is typically used first. This is followed by a buffer of pH 4 or pH 10.pH 10
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About the CWEA ECI Grade 1 exam
What is the CWEA ECI Grade 1 exam?
The CWEA Environmental Compliance Inspector (ECI) exams are designed for people currently working as, or aspiring to become, Environmental Compliance Inspectors in California.
The exams are administered by the California Water Environment Association (CWEA), a professional organization dedicated to wastewater professionals in California.
The CWEA ECI exams are categorized into four grades: Grade 1, Grade 2, Grade 3, and Grade 4:
- Grade 1 is the entry-level exam, ideal for beginners
- Grade 2 is more challenging and suited for supervisory roles
- Grade 3 is even more advanced, targeting middle-management positions
- Grade 4 is the most difficult and is intended for upper-management roles.
While CWEA certification isn't mandatory for a job as an Environmental Compliance Inspector, it can help you get a job and can also lead to a pay raise and other benefits.
Applying to take the exam
To apply for the exam, download an application form at cwea.org/certification/apply, fill it in, and email it to memberservices@cwea.org.
The exam costs $209 for CWEA members and $448 for non-members. You can pay this fee by entering your credit card details on the application form.
If the CWEA approves your application, they will send you an approval email. Once you have this email, you can schedule your exam appointment through Pearson VUE's website.
You can take the exam at a test center in the US or at home on your computer. The exam is offered four times a year: in spring, summer, fall, and winter.
There are no education or work experience requirements to take the exam.
Exam day
If you take your exam at a test center, arrive at least fifteen minutes early. Bring at least one photo ID. Your photo ID must be current, valid, and government-issued (e.g., state driver’s license or passport).
If you take the exam at home, you will need to check in to the testing system online 15—30 minutes beforehand. During the check-in, an online proctor will ask you to take photos of your testing space to ensure your room is private and secure. You will not be allowed books, paper, calculators, sticky notes, whiteboards, or chalkboards, and the proctor may ask you to remove such material before the exam. The proctor will monitor you throughout the exam.
Whichever method of taking the exam you choose, an onscreen calculator will be available. If you take the exam at a test center, you may also bring your own calculator as long as it is from the CWEA-approved calculator list.
After you finish the exam, your result will immediately appear on the computer screen.
Passing the exam
The CWEA ECI Grade 1 exam has 100 questions. To pass the exam, you will generally need a score of at least 75% (although this may vary depending on the exam's difficulty).
Keeping your certification
After you pass the exam, you will need to meet the following requirements to keep your certification:
- Submit 12 hours of continuing education every two years
- Pay the annual renewal fee
What if I fail the exam?
If you fail the exam, you can retake it after paying the exam fee again.
Cancelling the exam
To reschedule or cancel an exam, contact Pearson VUE at least 24 hours before the exam is set to start.
Topics on the exam
The CWEA ECI Grade 1 exam covers 19 KSAs (Knowledge, Skills, and Abilities). These are outlined below.
KSA 101: Sampling
This KSA is about sampling and is worth 7% of the exam. You will need to know about:
- sampling equipment and preservatives, including field blanks
- sampling procedures, including grab samples
- the terms turbidity and specific conductance
- the correlation between BOD and COD
- how to identify acids and bases
- mathematics, including:
- balancing chemical equations
- dilution calculations
- neutralization calculations
- calculating the pH of an aqueous solution
KSA 102: Documentation
This KSA is about documentation relating to environmental compliance and is worth 5% of the exam. You will need to know about:
- inspection reports
- chain of custody procedures (why they are important, the containers and preservatives required for chain of custody procedures, etc.)
KSA 103: Field and laboratory tests
This KSA is worth 4% of the exam and will test your knowledge of:
- field equipment (uses, preparation, and limitations)
- gases and chemicals identified by field tests
- identification of Total Toxic Organics
KSA 104: Inspection of pretreatment facilities
This KSA will test your knowledge of pretreatment facility inspection and is worth 9% of the exam. You will be tested on:
- common wastewater pollutants
- how to respond to facility violations
- reverse osmosis and its use in industrial processes
- rinse concurrent tanks and counter-current tanks
- photo, x-ray, and silver removal processes
- regulations related to wastewater discharges
- the Federal Water Pollution Control Act of 1972
- the Clean Water Act of 1977
KSA 105: Inspection of businesses
This KSA is like the previous KSA except it tests your knowledge of business inspection. The KSA is worth 9% of the exam and will ask you questions about:
- stormwater
- the pollution prevention hierarchy
- non-compatible pollutants
- spill response procedures
- laws
- regulations related to pollution prevention
- regulations related to stormwater requirements
KSA 106: Pretreatment devices
This KSA is worth 6% and will test your knowledge of pretreatment devices, such as grease traps, interceptors, clarifiers, and silver recovery units. You may also be asked about:
- ORP meters
- gases generated in grease interceptors
- the calculation of interceptor detention time
KSA 107: Maintainance of sampling equipment
This KSA is worth 4% and will ask you about:
- the maintenance and calibration of sampling equipment and gas detectors
- preservation methods according to 40 CFR 136
KSA 108: Use of sampling equipment
This KSA is worth 5% of the exam and will ask you about:
- how to select the right sampling pump for a given situation
- types of sampling (composite, grab, flow-proportional, discrete, etc.)
- methods of calibrating pH meters
KSA 109: Call-outs
This KSA is worth 3% of the exam and will ask you questions about:
- call-outs
- the investigation of illegal waste discharges
- emergency response procedures
- spill procedures
KSA 110: Interaction with customers and staff
This KSA is worth 4% and will test your ability to communicate effectively and appropriately with staff and customers.
KSA 111: Safety
This KSA is worth 8% of the exam and will test your knowledge of safety practices, including:
- personal protective equipment (PPE)
- maximum safe sound levels
- exposure limits of pollutants in the workplace
- confined spaces
- common gases encountered in sewer systems
KSA 112: Recording data from inspections
This KSA is worth 6% and will ask you questions about the recording of data for inspections. You will need to know about:
- the conversion of liquid measurements
- the calculation of flow rate, gallons discharged per day, etc.
- Information required in an inspector's notebook
KSA 113: Keeping equipment and worksites safe
This KSA is worth 6% and will test your knowledge about the maintenance of equipment, materials, and worksites in an orderly and safe fashion. You will need to know about:
- procedures to take when observing unsafe working conditions
- types of confined spaces
- concentrations of flammable gases that will cause combustion
- pathogens
- measuring gas levels with a gas detector
KSA 114: Staying current on developments in environmental compliance
This KSA is worth 3% and will ask you about the best sources to stay current on pretreatment regulations and the sources of information that workers in an Industrial User site should have access to.
KSA 115: Helping users maintain compliance with legal requirements
This KSA is worth 5% of the exam and will test you on maintaining program compliance with legal requirements through the issuing of permits and by guiding noncompliant users back to compliance.
KSA 116: Measurement of field conditions
This KSA is worth 4% and you will need to know how to measure various field conditions, including:
- effluent
- flow
- pH
- ORP
- atmospheric gas
- levels of combustibles
You will also need to know how to convert between different units of volume (gallons, liters, and cubic feet).
KSA 117: Sewer impact fees
This KSA is worth 2% and will ask you to measure and calculate sewer impact fees.
KSA 118: Reports
This KSA is worth 5% and will test your knowledge of preparing reports. You will need to know:
- how to calculate water usage
- terms relating to hazardous materials
- how to review safety data sheets
KSA 119: Sanitary sewer overflows
This final KSA is worth 5% and will ask you about:
- the different categories of sanitary sewer overflows
- sampling procedures of sanitary sewer overflows
